The Basic Idea for a Solution
To implement a solution to the 2 coloring problem, we need to visit each node of the graph, which can be done via a depth-first or breadth-first traversal. Initially, none of the nodes is colored so we can assign an arbitrary color to the first node. Once the traversal begins, we check two cases for a node n:
- One or more adjacent nodes of
nhave been assigned the same color.ncan be assigned the opposite color. - Two or more adjacent nodes of
nhave been assigned opposite colors. It is not possible to assignna valid color.
These two cases are shown in the figure below. The gray node has to be assigned a color.

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assert.equal(twoColorGraph(N, dislikes), false);var assert = require('assert');var twoColorGraph = function (N, d) { //your code here};try { N = 4; dislikes = [ [0, 1, 0, 1], [1, 0, 1, 0], [0, 1, 0, 1], [1, 0, 1, 0], ]; assert.equal(twoColorGraph(N, dislikes), true); console.log('PASSED: ' + 'First Test');} catch (err) { console.log(err);}try { N = 4; dislikes = [ [0, 1, 1, 1], [1, 0, 0, 0], [0, 1, 0, 1],OUTPUT
Results will appear here.