Good evening! Here's our prompt for today.
We're given a sorted singly linked list (that is, a linked list made of nodes with no pointers to the previous node) where the elements are already arranged in ascending order.
JAVASCRIPT
1// -9 -> -2 -> 3 -> 5 -> 9
2
3// Linked List Node Definition:
4function Node(val) {
5 this.val = val;
6 this.next = null;
7}Can you convert it to a binary search tree?

JAVASCRIPT
1// Tree Node Definition
2function Node(val) {
3 this.val = val;
4 this.left = null;
5 this.right = null;
6}Of course, there are many ways to build the BST, so any height balanced BST is acceptable. A height-balanced binary tree is just like it sounds-- the depth of the two subtrees of every node should never differ by more than 1.
Here's one tree that could be formed:
SNIPPET
1 3
2 / \
3 -2 9
4 / /
5 -9 5Constraints
- Number of nodes in the linked list <=
100000 - The nodes will always contain integer values between
-1000000000and1000000000 - Expected time complexity :
O(n) - Expected space complexity :
O(n)
Try to solve this here or in Interactive Mode.
How do I practice this challenge?
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'PASSED: ' + 'Linked list `4 -> 5 -> 6` is successfully converted to a BST'var assert = require('assert');​function listToBST(head) { // fill this in return head;}​function Node(val) { this.val = val; this.left = null; this.right = null;}​// Regular binary treesvar tree1 = new Node(4);tree1.left = new Node(1);tree1.right = new Node(3);​var tree2 = new Node(5);tree2.left = new Node(10);tree2.left.left = new Node(17);tree2.left.right = new Node(3);tree2.right = new Node(8);​// Binary search treesvar tree3 = new Node(6);tree3.left = new Node(3);​var tree4 = new Node(5);OUTPUT
:001 > Cmd/Ctrl-Enter to run, Cmd/Ctrl-/ to comment
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