Method 3: Modern Elegance with ES6 and Beyond
Step 1: Extract Only the Alphabets
In this method, we're tapping into the powerful arsenal of ES6 methods, specifically map and filter, to craft a more streamlined solution.
Creating an Alphabetic Array
First off, we extract only the alphabetical characters from the string and store them in a new array, which we'll call alphaOnly.
Here's how you can do it in multiple languages:
1std::string alphaOnly;
2std::copy_if (str.begin(), str.end(), std::back_inserter(alphaOnly), [](char c){return isalpha(c);} );Step 2: The Transformation Act
After creating our alphaOnly array, the next phase is where the real magic happens. We'll split the original string into an array and perform a transformation using map.
Returning Non-Alphabetic Characters
During this transformation, if a character does not match our Regular Expression criteria (i.e., it's not an alphabetical character), we simply return it in its current position, leaving it untouched.
Picture this as walking through a garden and only flipping the stones that have a specific marking, while leaving all others in their original state.
xxxxxxxxxxstd::string alphaOnly = "";for (char c : str) { if (std::isalpha(c)) { alphaOnly += c; }}std::vector<std::string> result;for (char c : str) { if (!std::isalpha(c)) { result.push_back(std::string(1, c)); }}